If z satisfies the equation modulus z -z =1+2i,then find the value of z
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23
given | z | - z = 1 + 2 i
complex numbers.
z = a + i b.
SO √(a²+b²) - a - i b = 1 + 2i
So b = -2. then √(a² +4) - a = 1
So a² +4 = a² + 2 a + 1
a = 3/2
complex numbers.
z = a + i b.
SO √(a²+b²) - a - i b = 1 + 2i
So b = -2. then √(a² +4) - a = 1
So a² +4 = a² + 2 a + 1
a = 3/2
Answered by
4
Given that
| z | = 1 + 2i
= 1 + 2 ( 1)
= 3
z =3
| z | = 1 + 2i
= 1 + 2 ( 1)
= 3
z =3
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