Question

if Z square + 1 upon z square is equal to 34 find the value of Z cube plus one upon z cube

Answer 1

Hi mate

Here us your answer

198

Hope this helps you

Plz mark as braniest

Answer 2

Answer:

$z^{3}+\frac{1}{z^{3}}=196$

Step-by-step explanation:

$z^{2}+\frac{1}{z^{2}}=34$

$\implies z^{2}+\frac{1}{z^{2}}+2\times z\times \frac{1}{z}=34+2\times z\times \frac{1}{z}$

$\implies \left(z+\frac{1}{z}\right)^{2}=34+2\\=36$

$\implies \left(z+\frac{1}{z}\right)=\sqrt{36}\\=6$

$Now, z^{3}+\frac{1}{z^{3}}\\=\left(z+\frac{1}{z}\right)^{3}-3\left(z+\frac{1}{z}\right)$

$=(6)^{3}-3(6)\\=6(36-3)\\=6\times 33\\=196$

Therefore,.

$z^{3}+\frac{1}{z^{3}}=196$

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