If z square+1/z square=11, find the value of z cube -1/z cube using only the positive values of z-1/z
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(z+ 1/z)² = z² + 1/z² + 2× a × 1/ z
(11)² = z² + 1/ z² + 2
z² + 1/ z² = 121 ‐ 2
z² + 1/ z² = 119
Also,
(z ‐ 1/ z)² = z² +1/z² ‐ 2 × z × 1/ z
(z‐1/z)² = 119 ‐ 2
z ‐ 1 / z = root 117
( z‐1/z )³ = z³ ‐ 1/ z³ - 3 ( z- 1/ z)
z³ - 1/z³ = 117 × root 117 + 3 × root 117
= (117 × 10.81 ) + ( 3× 10.81)
= 1265.54 + 32.43 = 1297.97 ( approximately)
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