Question

If z =t^5 - 3t^4 +2 t^3 +8 then find the dz/dt and find value of the derivative at t=1

Answer 1

Answer:

$\frac{dz}{dt} = \frac{d(}{dt} {t}^{5} - 3 {t}^{4} + 2 {t}^{3} + 8)$

$= 5 {t}^{4} - 12 {t}^{3} + 6 {t}^{2} + 0$

At t=1

$= 5 \times 1 - 12 \times 1 + 6 \times 1$

$= 5 - 12 + 6$

$= 11 - 12$

$- 1$

Step-by-step explanation:

This is required solution to the question.