Question

if √Z=x+iy, then |z|=​

Answer 1

Step-by-step explanation:

√z=x+iy

squaring on both sides

z=x^2+i^2y^2+i2xy

z=x^2-y^2+i2xy

|z|=√(x^2-y^2)^2+(2xy)^2

|z|=√(x^4+y^4-2x^2y^2+4x^2y^2

|z|=√x^4+y^4+2x^2y^2

|z|=√(x^2+y^2)^2

|z|=x^2+y^2

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