.if z = x + y. if we take x=-2,y =6 find z if we take x = 2,y= -6 find z
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Let sin–1x = α, sin–1y = β, sin–1z = γ.
Then x = sinα, y = sinβ, z = sinγ
=> sin–1x + sin–1y + sin–1z = π/2
=> sin–1x + sin–1y = (π/2) - sin–1z
=> α + β = (π/2) - γ
=> cos(α + β) = cos{(π/2) - γ}
=> cosα.cosβ - sinα.sinβ = sinγ
=> √(1-sin2α.√(1-sin2β) - sinα.sinβ = sinγ
=> √(1-x2)√(1-y2) - xy = z
=> √(1-x2)√(1-y2) = xy + z
=> (1-x2)√(1-y2) = (xy + z2)2
=> 1 – y2 – x2 + x2y2 = x2y2 + z2 + 2xyz
=> x2 + y2 + z2 + 2xyz = 1
Hope it helpful ✌️✌️
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