if z=x^y + y^x, then show that, d²/dxdy = d² 3/dydx
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Answer:
d2f(x, y)/dydx = 2 x + cos y
also, and this result is true in general:
d2f(x, y)/dxdy = d2f(x, y)/dydx
Step-by-step explanation:
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