if |z-z0|>r then the points on the circle is
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Answer:
The equation ∣z−z
0
∣=r represents
(Given : z
0
is a fixed complex number.)
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Answer
Correct option is
B
A circle with centre z
0
and radius r
Let z
0
=x
0
+iy
0
& z=x+iy
∴∣z−z
0
∣=r
∴∣x+iy−(x
0
+iy
0
)∣=r
Squaring both sides,
∣x+iy−(x
0
+iy
0
)∣
2
=r
2
(x−x
0
)
2
+(y−y
0
)
2
=r
2
This is the equation of a circle with radius r and (x
0
,y
0
) as centre.
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