if Z1=1+3i and Z2=3+i then show the following Z1/Z2
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Answer:
[3/5 +i(-4/5)]
Step-by-step explanation:
Z1=(1+3i) &Z2=3+i
now Z1/Z2
(1+3i)/(3+i)
taking conjugate
[(1+3i)(3-i)]/[(3+i)(3-i)]
(3-i+9i-3i²)/(9-i²)
we know i²= -1
{3-i+9i-3(-1)}/{9-(-1)}
{3-8i+3}/(10)
(6-8i)/(10)
now in (a+ib) form
[6/10 +i(-8/10)]
[3/5+i(-4/5)]
Thanku ...
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