Question

if Z¹=1+i and Z²=2+2i then ____ is not true
(A)z1 z2 | = | z1 | | z2 |
(B) | z1 + z2 | = | z1 | + | z2 |
(C) | z1 – z2 | = | z1 | – | z2 |
(D)|z1/z2| =|z1/z2|​

Answer 1

Answer:

may be my answer helps you

Step-by-step explanation:

∣z

1

∣+∣z

2

∣=∣z

2

+z

1

∣ ...(1)

let z

1

=a(cosA+isinA)&z

2

=b(cosB+isinB) where A=argz

1

&B=argz

2

Substitute z

1

&z

2

in eq (1)

⇒a+b=∣acosA+bcosB+i(asinA+bsinB)∣

⇒a

2

+b

2

+2ab=(acosA+bcosB)

2

+(asinA+bsinB)

2

⇒2ab=2ab(cosAcosB+sinAsinB)

⇒cos(A−B)=1

⇒A−B=0

∴argz

1

−argz

2

=0

Hence, option 'C' is correct.

Answer 2

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