If Z1 = 2 + 3i and Z2 = 3 - 2i then (Z1 .Z) =
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Z1=2+3i and Z2=3-2i
Therefore
Z1×Z2= (2+3i)(3-2i)
=2(3-2i)+3i(3-2i)
=6-4i+9i-6i²
=-6i²+5i+6
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