Question

If z1 = 3 + 2i and z2 = 4+ 3i and are complex numbers, find z1 z2

1) -6 - 17i
2) 6 + 17i
3) -6 + 17i
4) 6 - 17i​

Answer 1

Answer:

2. 6+17i

Step-by-step explanation:

z1z2= (3+2i)(4+3i)

= 12+9i+8i+6i²

= 12+17i+6(-1)

= 6+17i

as the i²=-1