Question

if z1 = 3-4i and Z2 = 1+2i then find the z1/z2​

Answer 1

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z1 / z2 = 0

3 - 4i / 1 + 2i = 0

3 - 4i = 0

i = 3 / 4

Answer 2

Answer:

3-4i/1+2i

=3-4i/1+2i× 1-2i/1-2i

= 3(1-2i) -4i(1-2i) / 1^2-2i^2

=3-6i-4i+8i^2/ 1-4i^2

=3-8-10i/1+16

=-5-10i/16

=-5/16-5i/8

Step-by-step explanation:

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