Question

if Z1 = (3,5) ; Z2 = (2,6) then find Z1,Z2​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given:

Z1 = (3,5)

Z2 = (2,6)

To Find:

Z1, Z2

Solution:

Z1,Z2 = $\sqrt{{[x2-x1]^{2} +[y2-y1]^{2} }$

         = $\sqrt{{[2-3]^{2} + [6+5]^{2} }$

         = $\sqrt{[1+1]}$

         = $\sqrt{2}$

Therefore, the value of Z1, Z2 is $\sqrt{2}$.