Question

if z1 = 4-3i and z2 = -12+5i show that |z1+z2| greater than |z1| + |z2|​

Answer 1

Answer:

$|4 - 3i - 12 + 5i| = |2i - 8| = 2i + 8$

this is for |z1+z2|

$|z1| + |z2| = |4 - 3i| + |5i - 12| = 4 + 3i + 5i + 12 = 8i + 16$

as given that

2i+8>8i+16

2(i+4)>2(4i+8)

i+4<4i+8

hence |z1+z2|<|z1|+|z2|

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Answer 2

Answer:

Your ques is has a correction in the theorem

|z1|+|z2| >|z1+z2|

And @shreeganeshsneha

ur ans is wrong u have taken modulus as wrong meaning here it is not making +ve .It means the distance b/w the two complex numbers.

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