if z1=4+5i and z2=-3+2i then z1/z2
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x1/z2=(4+5i)/(3+2i)
=(4+5i)(3-2i)/{3+2i)(3-2i)}
=12-8i+15i+10)/(9+4)
=(22+7i)/13
=(22/13)+(7/13)i
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