If z1=(6,3)and z2=(2,-1) then z1/z2
Answers
Answered by
19
z1 = 6+3i
z2 = 2-i
1/z2 = (2+i)/(2-1)
= 2+i
so
z1/z2 = (6+3i)(2+I)
= 3(2+i)²
= 3( 4 + 4i -1)
= 3( 3 - 4i)
ans = 9 - 12i
hope it helps you
@di
z2 = 2-i
1/z2 = (2+i)/(2-1)
= 2+i
so
z1/z2 = (6+3i)(2+I)
= 3(2+i)²
= 3( 4 + 4i -1)
= 3( 3 - 4i)
ans = 9 - 12i
hope it helps you
@di
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Answered by
0
Answer:
z₁ / z₂ is equal to 12/5 i - 9/5.
Step-by-step explanation:
z₁ = ( 6, 3 )
z₁ = 6 i + 3
z₂ = ( 2, -1 )
z₂ = 2 i - 1
z₁ / z₂ = ( 6i + 3) / ( 2 i - 1)
z₁ / z₂ = (6i + 3) / ( 2 i - 1) × ( 2 i + 1) / ( 2 i + 1)
z₁ / z₂ = (6i + 3) × ( 2 i + 1) / ( -4 - 1)
z₁ / z₂ = -12 +6 i + 6 i + 3 / -5
z₁ / z₂ = 12 i - 9 / 5
z₁ / z₂ = 12/5 i - 9/5
Therefore, we get that z₁ / z₂ is equal to 12/5 i - 9/5.
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