If z1 has positive real part and z2 has negative imaginary part , then z1+z2/z1-z2
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Answer:
The value of (z1+z2)÷(z1-z2) = i
Step-by-step explanation:
I am considering an example case satisfying the given condition of positive real part for z1 and negative imaginary part for z2
Let z1 be 1;
Let z2 be -i
(z1+z2)÷(z1-z2)= (1-i)÷(1+i)
=(1-i)² ÷ 2
= i
The value of (z1+z2)÷(z1-z2) = i
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