If Z₁ Z2 are two complex numbers such that |2₁| #12 and
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Answer:
∣z
1
+z
2
∣
2
=∣z
1
∣
2
+∣z
2
∣
2
⇒(z
1
+z
2
)(
z
1
ˉ
+
z
2
ˉ
)=∣z
1
∣
2
+∣z
2
∣
2
⇒z
1
z
2
ˉ
+
z
1
ˉ
z
2
=0
⇒z
1
z
2
ˉ
+
z
1
z
2
ˉ
ˉ
=0
Therefore, z
1
z
2
ˉ
is purely imaginary
⇒
z
2
z
1
+
z
2
ˉ
z
1
ˉ
=0
also
z
2
z
1
is purely imaginary.
⇒arg(
z
2
z
1
)=
2
π
and hence, O,z
1
,z
2
are vertices of right triangle.
Step-by-step explanation:
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