If z1andz2are two complex number then Re(z1z2) is equal to
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Let
Z1 = a+in
Z2= c+id
Now,
Z1Z2= (a+ib) (c+id)
=ac + adi +bci -bd
=(ac-bd) + i( ad+bc)
Therefore,
Re(Z1Z2)=( ac-bd)
Z1 = a+in
Z2= c+id
Now,
Z1Z2= (a+ib) (c+id)
=ac + adi +bci -bd
=(ac-bd) + i( ad+bc)
Therefore,
Re(Z1Z2)=( ac-bd)
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