Question

If zeba were younger by 5 years than what she really is then the square of her age would have been 11 more than five times her actually age. What is her age now?​

Answer 1

Explanation:

here is your answer on the attachment

Answer 2

Let the present age of Zeba = x years

5 years ago:

$\longrightarrow$$\sf{ {(x - 5)}^{2} = 5x + 11}$

$\longrightarrow$$\sf{ {x}^{2} - 10 + 25 = 5x + 11}$

$\longrightarrow$$\sf{ {x}^{2} - 15x + 14 = 0}$

$\longrightarrow$$\sf{(x - 1)(x - 14) = 0}$

$\longrightarrow$$\sf{x = 1 \: or \: x = 14}$

But x ≠ 1, because then x - 5 would be negative.

Hence, the present age of Zeba = 14 years.