Question

If zeba were younger by 5 years than what she really is, then the square of herage (in years) would have been 11 more than five times her actual age. What isher age now?

Answer 1

riiywrna a bit too late and the same problem and it

Answer 2

Let the present age of Zeba = x years

5 years ago:

$\longrightarrow$$\sf{ {(x - 5)}^{2} = 5x + 11}$

$\longrightarrow$$\sf{ {x}^{2} - 10 + 25 = 5x + 11}$

$\longrightarrow$$\sf{ {x}^{2} - 15x + 14 = 0}$

$\longrightarrow$$\sf{(x - 1)(x - 14) = 0}$

$\longrightarrow$$\sf{x = 1 \: or \: x = 14}$

But x ≠ 1, because then x - 5 would be negative.

Hence, the present age of Zeba = 14 years.