Math, asked by KateObat, 1 year ago

if Zeba were younger by 5 years then what she really is then the square of her age would have been 11 more than 5 times her actual age find present age

Answers

Answered by chandresh126
6
Let Zeba's present age be X.
Five years ago her age was (X-5). 
Now acc. to the question,
       (X-5)2 =11 + 5X
       X2-10X+25 = 11+5X
      X2-10X-5X+25-11 = o
     X2-15X+14=0
      X2-14X-X+14=0
      X(X-14)-1(X-14)=0
      (X-1)(X-14)=0
      so X=14 (or) X=1
    her age maybe 14 yrs or 1 yr.
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