Question

if Zena were younger by 5 yrs than what she really is, then then square of her age would have been 11 more than 5 times her actual age. what is her age now?? ​

Answer 1

Answer:

x=14 yrs

Step-by-step explanation:

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Answer 2

AnswEr :

Let the Zena Actual Age be x yrs.

Zena Age 5 Years Ago will be (x – 5) yrs.

$\underline{\bigstar\:\textsf{According to the Question Now :}}$

$:\implies\tt (Zena\:5\:yrs\:younger)^2=11+5(Actual\:Age)\\\\\\:\implies\tt (x-5)^2=11+5x\\\\\\:\implies\tt {x}^{2} + 25 - 10x = 11 + 5x\\\\\\:\implies\tt {x}^{2} - 10x - 5x + 25 - 11 = 0\\\\\\:\implies\tt {x}^{2} - 15x + 14 = 0\\\\\\:\implies\tt {x}^{2} - 14x - x + 14 = 0\\\\\\:\implies\tt x(x - 14) -1(x - 14) = 0\\\\\\:\implies\tt (x - 1)(x - 14) = 0\\\\\\:\implies \underline{ \boxed{\tt x = 1 \:yrs \quad or \quad x = 14\:yrs}}$

⠀

$\therefore\:\underline{\textsf{Ignoring impossible, actual age of Zena is \textbf{14 years}}}.$