if zero of 4x^2-8kxx-9 is negative of the other then find the value of k
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if we divide f(x) by 4 we obtain.
x^2-2kx-9/4=y/4
One root is the negative of the other. So, if the roots were 3 and -3, the quadratic could be factored as (x+3)(x-3)...
(x+a/b)(x-a/b)=x^2-2kx-9/4
we have a difference of squares. a=3, b=2, there is no linear term so k=0.
mark my answer brainlist plzz
if we divide f(x) by 4 we obtain.
x^2-2kx-9/4=y/4
One root is the negative of the other. So, if the roots were 3 and -3, the quadratic could be factored as (x+3)(x-3)...
(x+a/b)(x-a/b)=x^2-2kx-9/4
we have a difference of squares. a=3, b=2, there is no linear term so k=0.
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