Question

if zero of polynomial p( x) =(k+4)x square+ 13x+3x +3k is reciprocal of the other then k is equal to

Answer 1

p(x)=(k+4)x^2+13x+3x+3k
(k+4)x^2+16x+3k
let one zero be y
so another zero will be 1/y
y×1/y = 3k/k+4
1=3k/k+4
k+4=3k
4=2k
2=k
k=2

Answer 2

One zero= y

Another= 1/y

Y×1/y= 3k/k+4

1= 3k/k+4

K+4=3k

4= 3k-k

4=2k

K=4/2=2