if zero of the polynomial x²+(P+1)x+q are 2 and -3 then find the value of p and q
Answers
Answer:
ok let me think and then I will answer it
Answer:
Step-by-step explanation:
t is given that p and q are zeroes of the following polynomial.
p(x)=x2+(p+1) x +q
The relation between the zeros and coefficients of polynomial are,
Sum of roots =−(coefficient of x)coefficient of x2
Product of roots =constant term coefficient of x2Since p and q are roots of given equation, this gives p +q=−(p)1
p q=−q1 This further gives, p +q=−p (1)
p q=−q (2)
From (2), we have p q=−q p q +q=0
q (p+1)=0 This gives,
q=0 or p=−1From (1), when q=0 p=−p which is not possible
When p=−1 −1+q=−(−1) −1+q=1 q=1+1 q=2
Put this value in (2) 2p=−2 p=−1
Thus the required values are p=−1 and q=2