if zero of the polynomial x3-3x2+x+1 are a-b;a+b.Find "a" and "b"
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a+b+a+a-b=3.

3a=3
a=1
(a+b)a(a-b)= -1
a2-b2 =-1
1-b2=-1. (putting a=1)
2=b2
√2 =b...
3a=3
a=1
(a+b)a(a-b)= -1
a2-b2 =-1
1-b2=-1. (putting a=1)
2=b2
√2 =b...
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