Question

If zeroes f the polynomial x^3-3x^2+x+1 are a-b, a, a+b Find a and b

Answer 1

p(x) = x3 -3x2+x+1

Zeroes are a − b, a + a + b Comparing the given polynomial with px3+qx2+rx+1, we obtain p = 1, q = −3, r = 1, t = 1

Sum of zeros = a – b + a + a + b

-q/ p = 3a

–(-3)/1 = 3a

3 = 3a

a = 1

The zeroes are 1-b, 1, 1+b

Multiplication of zeroes = 1(1-b)(1+b)

-t/p = 1 – b2

-1/1= 1 – b2

1 – b2 = -1

1 + 1 = b2

b = ±√2

Answer 2

I think it is right answer