If zeroes of 6x^2 +kx +8 are equal and opposite, then k = ?
(please ans my question )
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Answer:
k=0
Step-by-step explanation:
let zeros be a n -a
6a^2 + ka +8 = 6a^2 -ka +8
ka =-ka
2ka =0
ka =0
if a is nonzero then k =0
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