Math, asked by kumarpritam092005, 8 months ago

 If zeroes of 6x^2 +kx +8 are equal and opposite, then k = ?
(please ans my question )​

Answers

Answered by sk0768173ph3gfb
2

Answer:

k=0

Step-by-step explanation:

let zeros be a n -a

6a^2 + ka +8 = 6a^2 -ka +8

ka =-ka

2ka =0

ka =0

if a is nonzero then k =0

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