Question

If Zeroes of a quadratic polynomial are ( 3 + √2) and ( 3 - √2), than find the quadratic polynomial
x² - 2√3x + 1
x² - 3x + 5
x² - 6x + 7
x² - (3 + √2)x + (3 - √2)​

Answer 1

Answer:-

According to the Question

It is given that ,

The zeros of a quadratic polynomial are ( 3+√2) & (3-√2)

• Sum of Zeros = (3+√2)

• Product of Zeros = (3+√2)

As we know that the quadratic polynomial is formed when its zeros are given .

Let , the quadratic polynomial be P(x)

• Quadratic Polynomial = x² - (Sum of Zeros)x + (Product of Zeros)

Substitute the value we get

$\longrightarrow$ P(x) = x² -(3 + √2)x + (3 -√2)

$\longrightarrow$ P(x) = x² - (3 +√2)x + (3 - √2)

• Hence, the required option is (d) x² - (3+√2)x + (3-√2).

Answer 2

Answer:

x^2 - (3+√2) x+(3 - √2) is the correct answer

Step-by-step explanation:

As we know that in a quadratic polynomial

Sum of Zeroes = -b/a

product of Zeroes= c/a

by using this formulawe can find the zeroes of the quadratic polynomial

Sum of zeroes= -(3+√2) /1

product of zeroes= (3-√2) /1

we get,

a=1, b= -(3+√2), c=(3-√2)

so the Quadratic polynomial will be

x^2 - (3+√2) x+(3 - √2)

Hope it's help you