Math, asked by Nishith7806, 8 months ago

If zeroes of polynomial 2x^2-3x+lambda and ax^2-6x+u are same tgen find tge value of :lambda×a/u

Answers

Answered by MaheswariS
10

\textbf{Given:}

\textsf{Zeroes of polynmials}

\mathsf{2x^2-3x+\lambda\;and\;ax^2-6x+u\;are\;same}

\textbf{To find:}

\textsf{The value of}\;\mathsf{\lambda{\times}\dfrac{a}{u}}

\textbf{Solution:}

\mathsf{Product\;of\;zeroes\;of\;2x^2-3x+\lambda\;is\;\dfrac{\lambda}{2}}

\mathsf{Product\;of\;zeroes\;of\;ax^2-6x+u\;is\;\dfrac{u}{a}}

\textsf{Since the zeroes of the given polynomials are same, we have}

\textsf{product of zeroes the corresponding polynomials also equal}

\implies\mathsf{\dfrac{\lambda}{2}=\dfrac{u}{a}}

\implies\boxed{\mathsf{\lambda{\times}\dfrac{a}{u}=2}}

\textbf{Find more:}

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