If zeroes of polynomial x^3-6x^2-3x+10 are in form a,a+b,a+2b. Find the zeroes
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Answer: a=3.14 or ni real value
Step-by-step explanation:
We know sum of zeroes=-b/a
So 6=3a+3b
a+b=2. I.e. 2-a=b
Also product of zeroes=-d/a
a^3 + 3a^2b +2ab=-10
Subs. The values of b,
This is the approximate value of irrational number. Else no real solution exists
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Answer:-1 ; -16 ; -31
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