If zeroes of polynomial x²+(a+1)x+b are 2 & -3 then find the value of (a+b)
Answers
Answered by
1
the sum of the roots =-b/a
2-3=-(a+1)/1
-1=-(a+1)
1=a+1
a=0
the product of the roots =c/a
2*-3=b/a+1
-6=b/0+1
-6=b
b=-6
2-3=-(a+1)/1
-1=-(a+1)
1=a+1
a=0
the product of the roots =c/a
2*-3=b/a+1
-6=b/0+1
-6=b
b=-6
Similar questions