Question

if zeroes of polynomial x2+ax-b are reciprpocals of each other then b =​

Answer 1

Answer:

b=-1

Step-by-step explanation:

x²+ax-b

here,

A=1

B=a

C=-b

As it is given that, One zero is reciprocal of the other

⇒α×1/α

we know that,

α×β=C/A

⇒α×1/α=C/A       (given)

⇒1=-b/1

⇒1=-b

⇒b=-1