If zeroes of quadratic polynomial x sq +( a+1)x +b are 2 and -3 , find values of a and b
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Answer:
clearly
sum of zeroe = coeff. of x / coeff.of x^2
2-3 = (a+1)
a=-1-1
a=-2
now
product of zeros = coeff. of constant / coeff. of x^2
2×-3 =b
b= -6
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