Question

If zeroes of quadratic polynomial x3+(a+1)x+b are 2 and -3, find value of a and b.

Answer 1

x^3 + (a+1)x + b = 0

Put x=2
8 + 2a + 2 + b = 0
2a + b = -10. eq. (1)

Put x=(-3)
-27 - 3a - 3 + b = 0
b - 3a = 30. eq. (2)

eq. (2)-(1)
-5a = 40
a = -8

Putting value of a in (2)
b = 30-24
b = 6

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Answer 2

Answer:

$\huge \tt \color{orange}{A=-8 ,</p><p>B=6}$

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