If zeroes of the polynomial
are a-b, a, a+b find a and b
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As we know that sum of zeroes
a+b+a+a-b=-(-3)
3a=3
a=1
product of zeroes=(a+b)(a)(a-b)
=(a^2-b^2)(a)=1
[(1)^2-b^2](1)=1
-b^2=2
b=-√2
pls pls mark it as brainiest
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