Question

If zeroes of the polynomial x^2 + (a+1)x+b are 2 and -3, then find the value of (a+b)

Answer 1

Answer:

Step-by-step explanation:

x^2 + (a+1)x+b

sum of zeros

2-3=-(a+1)

a=2-3-1=-2

product=2*(-3)=-6=b

b=-6