Question

if zeroes of the polynomial x^2+(alpha+1)x+b are 2 and - 3 then find the value of (a+b)

Answer 1

Hiii friend,

P(X) = X²+(a+1)X+b

Here,

A = 1 , B = (a+1) and C = b

Alpha = 2 and Beta =-3

Sum of zeros = -b/a

2 +(-3) = -(a+1)/1

2-3 = -a -1/1

-1 = -a-1/1

-a -1 = -1

a = 0

Product of zeros = C/A

2 × -3 = B/1

-6 = b/1

b = -6

Hence,

A = 0 and B = -6

Therefore,

(A+B) = (0+(-6)) = -6

HOPE IT WILL HELP YOU..... :-)