If zeroes of the polynomial x2+4x+2a are Alfa
and
then find the value of a
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Hello!
Compare x² + 4x + 2a with ax² +bx + c ,
a = 1 , b = 4 , c = 2a
According to the problem given ,
α and α / 2 are the zeroes of the polynomial ,
1 ) sum of the zeroes = - b / a
α + α/ 2 = - 4 / 1
( 2α + α ) / 2 = 4
3α = 8
α = 8 / 3
α² = 64 / 9 -----( 1 )
Product of the zeroes = c / a
α × α / 2 = 2a / 1
α² = 4a -------( 2 )
Therefore ,
Equation ( 1 ) = equation ( 2 )
64 / 9 = 4a
64 / ( 9 × 4 ) = a
16 / 9 = a
a = 16 / 9
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