Question

If zeroes of the polynomial x² + (p + 1)x + q are 2 and -3, then find value of p​

Answer 1

Answer:

p = 0

Step-by-step explanation:

2² + (p + 1)(2) + q = 0 ⇔ 2p + q = - 6 ........ (1)

(- 3)² + (p + 1)(- 3) + q = 0 ⇔ - 3p + q = - 6 ........ (2)

(1) - (2)

2p + 3p = 0 ⇒ p = 0  and q = - 6

f(x) = x² + x - 6