Question

if zeroes of x^2-kx+6 are in ratio 3:2, find k​

Answer 1

5 or - 5

Step-by-step explanation:

Let one root be 3x and other be 2x

Sum of roots = - b/a

3x+2x = -(-k)/1

5x=k

Product of roots = c/a

3x×2x= 6/1

6x²=6

X²=1

X= ±1

5(±1) = - 5 or 5

K can either be 5 or - 5