Question

If zeroes of x
2
-kx+6 are in the ratio 3:2, find k?

Answer 1

Given that :

Polynomial = x^2 - kx + 6 where a = 1, b = -k and c = 6

Let, the zeroes of given polynomial be 3y and 2y

Now, as we know that :

Sum of zeroes = -b/a

=> (3y+2y) = -(-k)/1

=> 5y = k ... (1)

And product of zeroes = c/a

=> (3y×2y) = 6/1

=> 6y^2 = 6

=> y^2 = 6

=> y = 1

On putting the value of y in equation (1) :

k = 5×1

=> k = 5

So, the value of k will be 5 ✔✔

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Hope it helps ☺

Fóllòw Më ❤