Question

If zeroes of x^2-kx+6 are in the ratio 3:2 find k

Answer 1

sum of zeros=k

product of zeros=6

k=5,k=-5

Answer 2

:Given - x² - kx + 6 = 0

The zeroes are 3x and 2x.

Sum of the zeroes = 3x + 2x = 5x which is equal to kSo,5x = k

Product of zeroes = 3x(2x) = 6x² which is equal to 6So,6x² = 6x = -1 / 1

Now, plugging the value of x in 5x = k,5(1) = k or 5(-1) = kk = 5 or -5

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