Question

if zeros of 2x^2 + 3x + p is 1\2 , find the value of p and also second zero​

Answer 1

Answer:

p = -2 = second zero

Step-by-step explanation:

$\alpha + \beta = \frac{ - b}{a} = - \frac{3}{2} \\ \alpha \beta = \frac{c}{a} = \frac{p}{2}$

Let ,

$\alpha = \frac{1}{2}$

$\frac{1}{2} + \beta = \frac{ - 3}{2} \\ \beta = \frac{ - 3}{2} - \frac{1}{2} \\ \beta = - 2$

Putting beta=-2 in their products...

$\frac{1}{2} \times - 2 = \frac{p}{2} \\ p = - 2$