If zeros of p(x)=x^2-5x+k are the reciprocal of each other,find the value of k
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Hi ,
p( x ) = x² - 5x + k
compare p( x ) with ax²+ bx + c = 0 , we
get ,
a = 1 , b = -5 , c = k
Let m and 1/m are two zeroes of p( x ).
Product of the roots = c/a
m × 1/m = k/1
1 = k
Therefore ,
k = 1
I hope this helps you.
: )
p( x ) = x² - 5x + k
compare p( x ) with ax²+ bx + c = 0 , we
get ,
a = 1 , b = -5 , c = k
Let m and 1/m are two zeroes of p( x ).
Product of the roots = c/a
m × 1/m = k/1
1 = k
Therefore ,
k = 1
I hope this helps you.
: )
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