Question

If zeros of poly.x2+(a+1)x+b are 2 and -3 find value of a and b

Answer 1

Step-by-step explanation:

Since zeroes are 2 and -3.

Let us first form a quadratic polynomial with zeroes 2 and -3. Then, the given polynomial is equal to our formed polynomial. Since they are equal, we will equate the coeffecients and find a and b.

So, quadratic polynomial is

$(x - 2)(x + 3) = 0 \\ {x}^{2} + 3x - 2x - 6 = 0 \\ {x}^{2} + x - 6 = 0$

The given quadratic equation is

${x}^{2} + (a + 1)x + b = 0$

So, by equating coeffecients

a+1=1. So, a=0 and b=-6.

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