Math, asked by sabzid2ubbap, 1 year ago

If zeros of polynomial 6x 2 +4x+2a are α and 1/a , then find the value of a.

Answers

Answered by vaibhav741852
2
p(x) = 6x^2 + x - 2 
To find the zeros, let p(x) = 0 
6x^2 + x - 2 = 0 
x^2 + (1/6)x - 1/3 = 0 
(x + 1/12)^2 - 1/144 - 48/144 = 0 
(x + 1/12)^2 - 49/144 = 0 
(x + 1/12)^2 - (7/12)^2 = 0 
(x + 1/12 + 7/12)(x + 1/12 - 7/12) = 0 
(x + 2/3)(x - 1/2) = 0 
x = -2/3 or x = 1/2 
Let α = -2/3 and β = 1/2 
α/β+ β/α 
= (-2/3) / (1/12) + (1/12) / (-2/3) 
= -24/3 - 3/24 
= -8 - 1/8 
= -65/8
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