If zeros of polynomial x³-6x²+x+1 are a-b, a and a+b, find a and b
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sum of the roots =-(-6)
a-b+a+a+b=6
3a=6
a=2
product of the roots =-1
(a-b)(a)(a+b)=-1
(a²-b²)(a)=-1
(2²-b²)(2)=-1
(4-b²)=-1/2
4+1/2=b²
9/2=b²
b=3/√2
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